$\left(x^2+2\left(x\right)\left(2\right)+2^2\right)$
$9x-3y+5+-x-y+4+-5x+4y-9$
$2mn-5mn+8mn-10mn+6mn-3mn+mn$
$9x-6\ge-18x-1$
$2x-4+x+3\:\:+x+5$
$\frac{dy}{dx}=\frac{\left(1-y^2\right)}{2x}$
$\frac{dy}{dx}=\frac{4}{\left(x^2+4\right)y}$
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