$\left(3\right)\left(-3\right)\left(-3\right)\left(-3\right)\left(-3\right)$
$\frac{1}{2}+\frac{3x}{4}\ge\frac{1}{5}-2x$
$\frac{3}{4}x\cdot5y^2$
$125x^3-729y^3$
$7-\left|1+\left(9-13\right)\right|$
$\sin\left(180-\left(a+b\right)\right)$
$\lim_{x\to4}\left(\frac{x^2-4x}{x^2+3x-4}\right)$
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