$\left(x\cdot y'+y\right)\cdot\sqrt{1+x^2}=x$
$m^2-6m-27=0$
$4-x<x+10$
$\frac{t^{3}+1}{t+1}$
$y'=2+2y+x+xy$
$y^4-3x^2-4=0$
$\left(+5\right)+\left(-1280\right)\left(-8\right)$
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