$\left(x^3-3x+2\right)^3$
$\frac{d}{dx}\left(x^3-x+3\right)$
$4x-9x+10=20$
$\int_1^2\left(6x+6\right)dx$
$\int\left(4x^3-15x\right)^{10}\left(4x^2-5\right)dx$
$\left(6\cdot16\right)+\left(3\cdot16\right)$
$2a^2-3a-44$
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