$5\left(-2\right)+2\left(3\right)\left(6\right)+3\left(-2\right)\left(6\right)$
$2x+9>3x$
$\frac{1}{a^{-5}}$
$\frac{12}{0}$
$\left(-2x^2y-2x\right)\frac{dy}{dx}=-\left(2xy^2+2y\right)$
$-4x^2-x^2-6x^2-4x^2$
$\tan^2\left(x\right)-2\tan\left(x\right)-10$
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