$\frac{1}{16x^3+4x^2}$
$20:\:-5$
$\int_{-1}^1\left(\frac{4}{x^2}\right)dx$
$\frac{x-9}{3}=\frac{56}{x+4}$
$\frac{8x^5y}{24x^3}$
$\frac{p^2}{225}-121$
$8x^2-17x+2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!