$\left(x+\frac{2}{5}\right)\left(x-\frac{3}{4}\right)$
$\frac{x^3+5x^2+6x+2}{x+2}$
$\frac{cota}{csca-1}=\frac{csca+1}{cota}$
$4x^2-5x+6$
$b\:-\:6\:=\:38$
$\frac{x^2-2x-37}{x^2-3x-30}$
$-5t^2+10t+1.7$
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