$\lim_{x\to1}\left(\frac{3}{x-1}\right)$
$\lim_{x\to\infty}\left(\ln\left(6x\right)-\ln\left(x+8\right)\right)$
$\left(-z^2\right)+12x+x+\left(-5z^2\right)+15z^2+8$
$\left(x^2+29\right)y'=xy$
$\left(6x^2y-1\right)\left(6x^2y+3\right)$
$25y^2+20y-5$
$+99=128$
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