$\left(3sinx-1\right)^2=2$
$4+8-5+1-12+6$
$\frac{1}{2}\cdot400\cdot400^2$
$\left(sinx\right)^2-\left(tanx\right)^2$
$3\left(10a+7\right)$
$\left(a+4ab^2+6xy^3\right)^2$
$45\cdot33\cdot30$
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