$x^2+5x=-5$
$\frac{\left(x^2-4x+4\right)}{x^2-4}$
$\frac{d^2}{dx^2}\left(\sin^2\left(x\right)\right)$
$\left(4x-1\right)\left(3x^2+3x-5\right)$
$2x^4-4^3-5x-2$
$\int_{\frac{-\pi}{4}}^{\frac{\pi}{4}}\left(secx\right)dx$
$2^2+8^2$
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