$\lim_{x\to\infty}\left(1+\frac{3}{x}\right)^{4x}$
$-546+-1570$
$x^3+y^3-6=0$
$5+4-6-9+19-18+15$
$\lim_{x\to-\infty}\left(\frac{x^8-25}{x-7}\right)$
$sen\left(2x\right)cos\left(x\right)=6sen^3\left(x\right)$
$\left(xw^2\right)^3$
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