$xy'-y=x^2\sin\:\:x,\:\:y\left(x\right)=6x-x\cos\:\:x$
$y^{-\frac{4}{3}}$
$\left(-\infty\right)^2$
$5x^2+32x+12$
$-49x^2y^6z^{10}-9^{12}$
$\left(3x-4y\right)\left(2x-y\right)$
$4\left(x^{-4}y\right)^{-3}$
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