$\frac{2}{x}-\frac{3}{x+3}$
$cos\left(x\right)=\tan\left(x\right)$
$\int\:\frac{1}{\left(\sqrt{36-\left(x-6\right)^2}\right)}dx$
$-3f^2-90f-675$
$a^2-2a-35=0$
$\frac{m^3-1}{m+1}$
$\int\frac{6}{x^2-5}dx$
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