$4\left(3+2x\right)<-\left(6x+8\right)$
$s^2-s+4$
$62\cdot22$
$\int\frac{x^3-6x+1}{x^4+6x^2+8}dx$
$5cos\left(t\right)\:tan\left(t\right)$
$\int2\sec^3\left(6x\right)dx$
$\frac{-4ab^2+14a^4c}{-2a^2c^2}$
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