$a=\frac{\left(3x+y\right)^{2}-\left(3x-y\right)^{2}}{12}$
$7 x ^ { 2 } + x 4 - y ^ { 2 } = 4$
$x^6+x^6+2xy=25$
$x^2-10x\:-11$
$\:\left(1+tan^2x\right)cotx=secx\:cscx$
$a^2+25+10^2$
$\lim_{x\to-6}\left(\frac{x^2+2x-4}{x+4}\right)$
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