$3y^2dy=dx$
$cot\:x.\:cos\:x.\:sen\:x=sen^2$
$\left(\frac{4x-5}{3}\right)=\left(\frac{3x-7}{2}\right)$
$2.10\::\:\left(-5\right)\:.\:6\:$
$62,3-56,4$
$y^2=x+4$
$\left|-\frac{2}{3}+\frac{4}{3}\right|$
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