$\int\left(3x+6\right)\frac{1}{\left(2x^2+8x+3\right)^2}dx$
$3x\:-\:9\:=\:3$
$\lim_{x\to\infty}\left(e^{x+e^{-x}}-e^x\right)$
$\frac{6x+\sqrt{12}}{2}$
$\left(2x^{2}+3x-2\right)\cdot\left(-5x+1+3x^{2}\right)$
$\sqrt[3]{x+1},\:a=1$
$10-3x-x^2<0$
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