$\frac{dy}{dx}\left(2x^3+y^2=tan\left(xy\right)\right)$

$\left(a^6\:-\:b^6\right)\left(a+b\right)^3$

$\int_0^{2\pi}\left(\frac{1}{10-6cos\left(x\right)}\right)dx$

$\tan x+1=\left(5\right)$

$\frac{d}{dx}\sqrt{1-x^2}$

$x^2+2y-24=0$

$\frac{d}{dx}\left(y^2-2xy=a^2\right)$