$-12-3-7+4-2+1+5$
$25z^4+10z^4+1$
$\frac{1}{4}\cdot0$
$\lim_{x\to2}\frac{3x^2}{4-x^2}$
$\int\frac{12x+8}{3x^2+4x}dx$
$\frac{dy}{dx}=-\frac{x+y+1}{2x+2y+3}$
$\int_2^4\left(\sqrt{x^2-8}\right)dx$
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