$\ln\sqrt{x+1}=1$
$a\left(g\right)=\left(3.00m\frac{m}{c^3}\right)v$
$9x^2-35=6x$
$\int\frac{\ln\left(2x\right)}{x^5}dx$
$\frac{2}{3}x\cdot\left(\frac{3}{2}x-2y\right)$
$\int\frac{2x+3}{\sqrt{x}\left(1+\sqrt[3]{x}\right)}dx$
$\left(2x^2+3y^3\right)^4$
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