$\frac{d}{dx}xe^{xy}=y^2-1$
$a^2-a<0$
$\frac{4x}{x^2+1}=\frac{8}{5}$
$\frac{3.6}{1273}$
$\left(8b^5-6n^4\right)^3$
$\frac{\sqrt{x-2}+\sqrt{x+3}}{2}=a$
$\:\:\left(\sqrt[4]{16-4x^2}\right)$
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