$\int\frac{3x-1}{x^2-4x+8}dx$
$7^4\cdot7^{-4}$
$\frac{q}{7}-3>\frac{\left(q-4\right)}{3}+1$
$\frac{\sqrt{3}}{\sqrt{x}}$
$\left(x+1\right)y'=x\left(y^2\:+1\right)$
$\frac{35m^2n}{7m^{-2}n^{-1}}$
$\int\frac{1}{\sqrt{9-4x}}dx$
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