$\frac{x^3-x^2+3x+5}{x-2}$
$\left(4vf-2ab\right)^2$
$39-\left(-39\right)$
$\left(1-sen^2b\right)\left(1+tan^2b\right)=1$
$\frac{5^3-125}{5^25\left(5\right)}$
$\int\frac{sec\:x}{tan\:x+ctg\:x}dx$
$am^2-6mn+m^2$
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