$\frac{d}{dx}x^3+4x+9$
$-2x+5y-z=10$
$\frac{-4}{2}+\frac{7}{7}$
$1024\cdot32\cdot256$
$\int\frac{x}{\sqrt[3]{t^2+9}}dx$
$\frac{x^1-1}{x^2-1}$
$\frac{d^2y}{dx^2}=x^2-2y$
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