$\frac{3}{2ab}+\frac{4}{2ab}$
$\int\frac{17xe^{2x}}{\left(1+2x\right)^2}dx$
$\left(y+1\right)dx+\left(x+2\right)dy=0$
$x+5\le-2$
$x\left(\frac{1}{2}x^2-\frac{1}{8}\right)$
$-8\left(-4x\right)+-4\left(6\right)$
$\frac{x+6}{x-4}=\frac{1}{x+1}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!