$f\left(x\right)=3x^2+5-6$
$\frac{3a^5-11a^3-3a^2+2}{4a^2-2}$
$16-h^2$
$1.056-\left(-0.124\right)$
$9^{x+8}=81^{x-1}$
$\cos\left(2a\right)\sec^2\left(a\right)=1-\tan^2\left(a\right)$
$\ln\frac{y}{x^2+1}=1$
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