$x^2\left(x^3-1\right)^5e^{-2x}$
$y=\frac{1}{\sqrt[3]{x^2}}-x$
$\lim_{x\to\infty}\frac{\sqrt{x^2+9}}{3x^2+5}$
$5a^2b\cdot3a^{-3}b^4$
$\left|\left(\frac{3}{2}\right)^{-2}\right|^3=\left(\frac{3}{2}\right)^{-6}$
$2\int te^{-3t}dt$
$\frac{x^2-27}{x-3}$
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