$\frac{\left(x^4-4x+3\right)}{x^3+2x^2+x}$
$x2-16x$
$foci\:x^2=-16y$
$7+2x\ge1-x$
$x^3+6x^2+2x+12$
$1.8\cdot9.81$
$\:\left(\:b\:+\:3\:\right)\:.\:\left(\:b\:-\:10\right)$
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