$3x^2+x-3$
$\left(4x^4-1\right)\left(x^4+3\right)$
$216-y^6$
$7a+9b+6a-4b-9a+18c$
$\frac{3x^4-5x^2+x-3}{x^2+1}$
$5mn\left(3m+4n+9\right)$
$\lim_{x\to\infty}\left(\frac{x^4-4x^2+x}{x^3-x+5}\right)$
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