$4x^2+y^2=36$
$10xy\:+\:6xy$
$\int\frac{3x}{\sqrt{2-x^2}}dx$
$3\left(x^2\right)^2\left(x\right)$
$10^2+y^4-14y-24$
$y^2=\frac{2}{3}x^3+2c$
$x^2-32x+64$
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