$x-x-6\ln\left(12\right)x+3$
$\left(3x-6y\right)^3$
$1\:>\:2\:+\:3\:$
$z^2-24z+49$
$y=\frac{\frac{1}{3x}}{1-\frac{1}{3x}}$
$72t^2-12t-24$
$\frac{3}{5}+\frac{1}{5}+0.7$
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