$\frac{\left(x^2+6x+9\right)\left(x+1\right)}{\left(x-5\right)}$
$\left(5x^3+x\right)^3$
$4\le x-\frac{1}{2}$
$8x-6x+3x-5x+4-6$
$6\frac{dy}{dx}+5y=0$
$2\cdot5+3\cdot2$
$\int\frac{\left(4+x\right)^2}{\sqrt{x}}dx$
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