$c^2-4c-320$
$\left(4m^2n^3-3m^3n^2\right)^3$
$\left(\frac{2}{9}m^3c^4-\frac{3}{8}b^2f^5\right)\left(\frac{3}{8}b^2f^5+\frac{2}{9}m^3c^4\right)$
$2x+20=-30$
$5e-2e$
$ab+bc$
$-3x^2-24x-47$
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