$\lim\:_{x\to\:\infty\:}\left(\frac{x^2}{\:2^x}\right)$
$\lim_{x\to0}\frac{e^{4x}-1}{x}$
$\tan\left(\frac{a}{2}\right)=\csc-\cot$
$\cos\left(2x\right)=1.1279$
$3x^2-6x=3$
$\left(2x+1\right)\left(27x^3-108x^2+144x-64\right)$
$6x\left(-10\right)$
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