$\frac{dy^3}{dx^3}=x+senx$
$\frac{\left(3x^4+2x^3-5x^2+x+1\right)}{x-1}$
$m^2+5^2$
$30-25.45$
$9ab\:+\:7ab$
$\int\frac{6}{x^2-5x+6}dx$
$\:\frac{\left(1-cos\:u\right)\left(1+cos\:u\right)}{cos^2u}=\:tan^2u$
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