$2+3x\le8$
$\frac{x^3+3x}{x^2-2x-3}$
$\left(-15a^nb^3\right)\cdot\frac{4}{5}$
$5\sqrt[3]{8}-4\sqrt[5]{-32}+2\sqrt{64}$
$\lim_{x\to1}\left(\frac{x^2+6x-7}{2\sqrt{x}-2}\right)$
$9\cdot4+6\cdot4$
$1+5\cdot_{\left(4\cdot7+5\cdot_{\left(15-4\cdot5\right)}\right)}-3\cdot\left(7-4\right)$
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