$0.75\:\:\frac{3}{5}$
$68-\left(-93\right)-72+\left(-3+124\right)$
$5cosx+6=10cosx+5$
$\int\frac{1}{\left(4+x\right)^2\left(10+3x\right)}dx$
$\frac{532.154}{24}$
$\lim_{y\to-h}\left(\frac{y+h}{h^2-y^2}\right)$
$450+450$
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