$2.10\::\:\left(-5\right)\:.\:6\:$
$\left(4m^5+7\right)\left(-2+4m^5\right)$
$\left(5y-2\right)\left(2x^3-y^2+3y-4\right)$
$2x+1\:+\:2x-1$
$\left(z^2-4\right)^3$
$-4\:+\:5x\:-\:7$
$\frac{\ln\left(\infty\right)}{\sqrt[3]{\infty\:}}$
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