$8\left(p-6\right)>4\left(p-4\right)$
$\lim_{x\to0}\frac{2-\sqrt{4-x}}{3-x}$
$y^2=\frac{-x^4}{4}+\frac{32}{3}$
$18+x=27$
$25z^2-20z+4$
$\lim_{x\to\infty}\frac{2x}{e^x}$
$f\left(x\right)=in\left(x^3-x^2\right)$
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