$3-x^3=3-4x$
$-6\left(5x^2-3xy\right)-8y^2-2xy$
$5x-15+20x-5+3x+1$
$\frac{a^9}{a^3}$
$y=t\left(t+1\right)\left(t+2\right)$
$6b\left(7b+11\right)$
$\lim_{x\to0}\frac{6x^3-4x}{2x^4+x}$
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