$32x^3\:10xy$
$\left(7x+2x^4\right)$
$\frac{\left(secx+1\right)}{tanx}=cscx$
$7+5+9+12+8+3$
$\frac{x^4}{4}+\frac{x^3}{3}-2x^2-4x=0$
$\lim_{y\to x^2-x}\left(\frac{yx}{x+y}\right)$
$3-tan^2\left(\theta\:\:+\frac{\pi\:\:}{4}\right)=6.89$
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