$\frac{1}{16}y^4+\frac{1}{8}y^2+1$
$\frac{16x^8-1}{2x^2-1}$
$\left(2x^{2a-3}-3y^{4a+1}\right)^2$
$10\:cm\:b\:20cm\:\sqrt{300}$
$-34.71-100.08+111.62+92.93-27.27$
$6-2.48-1.263$
$\lim_{t\to infinito}\left(5t^4\cdot e^{\left(-2t\right)}\right)$
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