$\int\left(\sin^3\left(3x\right)\cdot\cos\left(3x\right)\right)dx$
$\int\:t^2\sqrt{1+t}dt$
$\frac{d}{dx}8x^3+6x^2=4xy^2-7y^3-9$
$-3-3-1+1$
$\frac{2x^3}{x^1}$
$1+\frac{-4x-3}{3+x^2}\:\left(\:8\right)$
$8x+3+4x+2$
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