$\left(13x+5\right)\left(13x-8\right)$
$1-2\tan\left(x\right)^2=\tan\left(x\right)^2$
$2x^2+8x-\:16$
$\left(5p+3q+2w\right)^2$
$-5=25$
$y=\sqrt[3]{\frac{\left(x+2\right)^2\left(x^2+3\right)}{\left(3x-5\right)^5}}$
$\frac{yx+5x}{x^2+1}$
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