$x^2+4x=7x-8$
$\left(2x+3y\right)\left(5x-4y\right)$
$-3\left(2d+4\right)-5\left(d-6\right)$
$\frac{dy}{dx}\left(2x^5+5y^5=7xy\right)$
$\int\left(\sqrt{9x^2-1}\right)dx$
$-1\:=\:4\cos^2x\:-\:2$
$6k\:x\:7k$
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