$\left(3x^2-y\right)^5$
$2a^2+a=1$
$\int\frac{x^2+5x+4}{\left(x-3\right)^2}dx$
$\sec\left(a\right)\cos\left(a\right)=\tan\left(a\right)+\cot\left(a\right)$
$\int\:\left(x^2+3\right)^2dx$
$\sqrt[25]{1}$
$-8tan\left(x\right)-8=0$
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