$\left(2ax-1\right)^2$
$\int_0^1\left(\frac{1}{2x-5}\right)dx$
$500.000+241$
$7z=-21$
$\int\left(3x-3\right)^{18}dx$
$\frac{\sin\left(4x\right)}{1+\cos\left(4x\right)}=\tan\left(2x\right)\:\:$
$\frac{a^3-8}{a^2+2a+4}$
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