$72=39+b$
$4^2a^4b^2$
$\left(5\sqrt{u-1}\right)\left(x^2+3\right)$
$\left(x^5+3\right)^4$
$\frac{-5\:+\:x}{22}=-1$
$20y^2-y-4$
$\sqrt[3]{8}a^3$
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