$7x-3y+7y-5x+8x$
$\lim_{x\to2}\left(4x-5\right)$
$\frac{m^2+1}{m-7}$
$\frac{\pi}{6}-\pi$
$\left(-4\right)\left(-3\right)+7\left(-4\right)$
$\lim_{x\to0}\left(\frac{\log\left(\log\left(1-x^2\right)\right)}{\log\left(\log\left(\cos\left(x\right)\right)\right)}\right)$
$5x^2+3x-36$
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