$\lim_{x\to0}\left(\frac{7x\left(cos\left(2x\right)\right)-1}{sin\left(8x\right)-8x}\right)$
$3x^2-8x-8=0$
$\int\frac{y^2+20y+100}{\left(y^2+100\right)^2}dy$
$\frac{dy}{dx}=3xy+3$
$\left(3m^5+4\right)\left(3m^5-4\right)$
$\lim_{x\to2}\left(\ln\left(3+x\right)\right)$
$1-2\cos+\cos^2=\sin^2$
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