$x^2+12x-13=0$
$-3^2+-6-8$
$\left(3-5\right)-\left(6-3\right)$
$3\cdot\infty^2+3\cdot\infty-17$
$\left(\frac{1}{2}a^2-3b\right)$
$\left(x^{2\:}3x\right)^2$
$\frac{d^2}{dx^2}\left(\frac{x+2}{x-2}\right)$
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